Using the standard normal curve find the zscore if the area
Using the standard normal curve find the z-score if the area
a) between –z and z is 99.49
b) to the right of z is 34.46.
Solution
a)
In this case, then by symmetry, the area to the left of -z is (1-0.9949)/2 = 0.00255.
Thus, by table/technology, the value of -z with this left tailed area is
-z = -2.80064873
Hence,
z = 2.80064873 [ANSWER]
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b)
If the area to the right of z is 0.3446, then the left tailed area is 0.6554.
We get the z score from the given left tailed area. As
Left tailed area = 0.6554
Then, using table or technology,
z = 0.399940964 [ANSWER]
