A person capable of swimming 45 mph swims across a 015mile w
A person capable of swimming 4.5 mph swims across a 0.15-mile wide river. The river current has a speed of 8.0 mph. How far down river will the person be upon reaching the other side? A passenger rides on an airplane with an acceleration vector of If the passenger drops an object, what acceleration would the object appear to have to an observer in the plane?
Solution
3. Person\'s horizontal velocity = 4.5 mph
Time taken to cover the horizontal distance = 0.15/4.5 hour
Person\'s vertical velocity (River current) = 8.0 mph
The vertical distance (distance in the direction of river current) = 8x0.15/4.5 = 0.27 miles
4. Airplane acceleration vector with respect to ground aGA= -3.5i + -7j
where i & j are unit vector along x & y axis respectively
Object\'s acceleration vector with respect to ground aGO = -9.8k
where k is unit vector along z axis .
So acceleration of object with respect to an observer in the plane aAO = aGO - aGA
aAO = 3.5i +7j - 9.8k
