On average 64 of Finite Mathematics students spend some tim

On average 64 % of Finite Mathematics students spend some time in the Mathematics Department\'s resource room. Half of these students spend more than 90 minutes per week in the resource room. At the end of the semester the students in the class were asked how many minutes per week they spent in the resource room and whether they passed or failed. The passing rates are summarized in the following table:

If a randomly chosen student did not pass the course, what is the probability that he or she did not study in the resource room?

Solution

Let

P = passed
S0 = did not study
S1 = studied in the resource room 1 to 90 minutes
S2 = studies in the resource room more than 90 minutes

Thus,

P(S0|P\') = P(S0 and P\') / P(P\')

Now,

P(P\') = P(S0) P(P\'|S0) + P(S1) P(P\'|S1) + P(S2) P(P\'|S2)

As

P(S0) = 1- 0.64 = 0.36
P(S1) = (1/2)*0.64 = 0.32
P(S2) = (1/2)*0.64 = 0.32

Thus,

P(P\')= 0.36*(1-0.31)+0.32*(1-0.46)+0.32*(1-0.69) = 0.5204

and

P(S0 and P\') = 0.36*(1-0.31) = 0.2484

Thus,

P(S0|P\') = P(S0 and P\') / P(P\') = 0.2484/0.5204

= 0.477325135 [ANSWER]