Consider the following hypotheses Which of the following sam
Consider the following hypotheses:
Which of the following sample information enables us to reject the null hypothesis at = 0.01 and at
= 0.10? Use Table 1.
| Consider the following hypotheses: | ||||||||||||||||||||||
| H0: p 0.45 | ||||||||||||||||||||||
| HA: p < 0.45 | ||||||||||||||||||||||
| Which of the following sample information enables us to reject the null hypothesis at = 0.01 and at
|
Solution
a)
Formulating the null and alternatuve hypotheses,
Ho: p >= 0.45
Ha: p < 0.45
As we see, the hypothesized po = 0.45
Getting the point estimate of p, p^,
p^ = x / n = 0.330275229
Getting the standard error of p^, sp,
sp = sqrt[po (1 - po)/n] = 0.047651256
Getting the z statistic,
z = (p^ - po)/sp = -2.512520773
As this is a 1 tailed test, then, getting the p value,
p = 0.005993602
Thus, we REJECT BOTH AT 0.01 AND 0.10. [ANSWER]
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b)
Formulating the null and alternatuve hypotheses,
Ho: p >= 0.45
Ha: p < 0.45
As we see, the hypothesized po = 0.45
Getting the point estimate of p, p^,
p^ = x / n = 0.339222615
Getting the standard error of p^, sp,
sp = sqrt[po (1 - po)/n] = 0.029572932
Getting the z statistic,
z = (p^ - po)/sp = -3.745904713
As this is a 1 tailed test, then, getting the p value,
p = 8.98724E-05
Thus, we REJECT BOTH AT 0.01 AND 0.10. [ANSWER]
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c)
Formulating the null and alternatuve hypotheses,
Ho: p >= 0.45
Ha: p < 0.45
As we see, the hypothesized po = 0.45
Getting the point estimate of p, p^,
p^ = x / n = 0.39
Getting the standard error of p^, sp,
sp = sqrt[po (1 - po)/n] = 0.066480395
Getting the z statistic,
z = (p^ - po)/sp = -0.90252172
As this is a 1 tailed test, then, getting the p value,
p = 0.183389894
Thus, we DO NOT REJECT FOR BOTH 0.01 AND 0.10.
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d)
Formulating the null and alternatuve hypotheses,
Ho: p >= 0.45
Ha: p < 0.45
As we see, the hypothesized po = 0.45
Getting the point estimate of p, p^,
p^ = x / n = 0.39
Getting the standard error of p^, sp,
sp = sqrt[po (1 - po)/n] = 0.024333213
Getting the z statistic,
z = (p^ - po)/sp = -2.465765601
As this is a 1 tailed test, then, getting the p value,
p = 0.006836039
Thus, we REJECT BOTH AT 0.01 AND 0.10. [ANSWER]


