You know the train left the Midvale station at exactly 630 p

You know the train left the Midvale station at exactly 6:30 pm and arrived at the Sandy station 164 seconds later. Distance between the stations is 3847 meters.

Data from Midvale station (0 meters) to Sandy Station (3847 meters)

1. Find the average velocity between stations. Give your answer in miles per hour.

Solution

The question says to find the average velocity between stations that means , we will need velocity for each station and then we can take its average , so lets find the average velocity for each station

velocity= distance travelled/time taken

velocity for 1st station = 85.7/17 = 12.24

velocity for 2nd station = (306-85.7)/(16-9) = 220.3/9=24.47

velocity for 3rd station = (675-306)/(31-16) = 369/15=24.60

velocity for 4th station = (995-675)/(44-31) = 320/13=24.61

velocity for 5th station = (1337-995)/(58-44) = 342/14=24.42

velocity for 6th station = (1655-1337)/(86-71) = 318/13=24.46

velocity for 7th station = (2030-1655)/(71-58) = 375/15=25

velocity for 8th station = (2370-2030)/(100-86) = 340/14=24.28

velocity for 9th station = (2490-2370)/(105-100) = 120/5=24

velocity for 10th station = (2886-2490)/(121-105) = 396/16=24.75

velocity for 11th station = (3198-2886)/(134-121) = 312/13=24

velocity for 12th station = (3802-3198)/(159-134) = 604/25=24.16

velocity for 13th station = (3847-3802)/(164-159) = 45/5=9

total velocity for all the stations = 12.24+24.47+24.6+24.61+24.42+24.46+25+24.28+24+24.75+24+24.16+9 =289.99

average velocity between stations = total velocity/total stations =289.99/13=22.30

now we need to convert 22.30m/sec to miles/hour

1 m/sec = 2.23694 miles/hr

22.30 m/s = 49.88 miles/hour

answer = 49.88 miles/hour