Using induction prove 8 divides 7n 3n 2SolutionPn7n 3n 2

Using induction, prove 8 divides 7^n + 3^n - 2

Solution

P(n):7^n + 3^n - 2

put n=1

P(1)=71 +31 -2=7+3-2 =8

8 dvisble by 8

so P(1) is true

Assume p(K) is true

P(k)=7^k+ 3^k - 2

P(k+1)=7^(k+1)+3(k+1)-2

=7k .7+3k ..3-2

=7(7k +3k) -4 3k +14

=7(7k +3k -2]+14 +4.3k -2

=4[3k +3]

[3k +3] is always even and 3k is always odd

so 3k +3 is always divisibe by 2

4*2x --->8

divisible by 8

hence

P(k+1) is true

by principle of mathematical induction

for P(n )belongs to N

8 divides 7^n + 3^n - 2

Using induction, prove 8 divides 7^n + 3^n - 2SolutionP(n):7^n + 3^n - 2 put n=1 P(1)=71 +31 -2=7+3-2 =8 8 dvisble by 8 so P(1) is true Assume p(K) is true P(k)

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