Homework SourseFind the equation of the tangent line to the curve y3xcosx a
Find the equation of the tangent line to the curve y=3xcosx at the point (pi, -3pi).
The equation of this tangent line can be written in the form y=mx+b where
m=?
and
b=?
The equation of this tangent line can be written in the form y=mx+b where
m=?
and
b=?
Solution
we have,
y\' = 3 cos x - 3x sin x
SO, y\' at x = , is : -3 - 0 = -3
SO, the equation of tangent is:
y-(-3) = (x-)(-3)
or,
y+3x +6 = 0
where, m = -3 , b = -6
