Find the vertex focus and directrix of the parabola Graph th

Find the vertex, focus and directrix of the parabola. Graph the equation. Y^2 + 6y= 4x + 15

Solution

given parabola y2+6y =4x+15

y2+6y+9 =4x+15+9

(y+3)2=4x+24

(y+3)2=4(x+6)

(y-(-3))2=4(x-(-6))

vertex = (-6,-3)

4a =4

=>a=1

focus = (-6+1,-3)

focus = (-5,-3)

directrix is x =-6-1

directrix is x =-7

Find the vertex, focus and directrix of the parabola. Graph the equation. Y^2 + 6y= 4x + 15Solutiongiven parabola y2+6y =4x+15 y2+6y+9 =4x+15+9 (y+3)2=4x+24 (y+

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