The ammeter shown in the figure below reads 250 A Find I1 I2

The ammeter shown in the figure below reads 2.50 A. Find I_1, I_2, and epsilon. (R = 6.90 ohm) I_1 = I_2 = I_3 =

Solution

Given, R = 6.90 Ohms. use the junction rule, we get

     I1 + I2 = 2.50 A

use the loop rule, we get

    15 = R*I1 + 5*2.50

then, the current, I1 = 0.362 A

therefore, the current is,

     I2 = 2.50 - I1 = 2.138 A

Hence, the emf is,

     emf = 2*I2 + 5*2.50 = 16.776 V = 16.8 V