CALCULATIONS 3 The input stream to a 2B1Q encoder is 10 01 1
CALCULATIONS:
3. The input stream to a 2B/1Q encoder is 10 01 10 11, what is the output stream? [chapter 4]
4. How many invalid (unused) code sequences can we have in 9B/13B encoding? [chapter 4]
Solution
3) 2B1Q(2 Binary 1 Quarternary) - data patterns of size 2 bits are encoded as one signal element belonging to a four-level signal(4 voltage levels)
out put stream will be { +3, -1, +3, +1 }
4) 9B/13B encoding- here a data pattern of size 9 bits are encoded by using 13 bits. using 9 bits we can represent 29 = 512 numbers.
using 13 bits we can represent 213 = 8192 numbers. in which we only need 512 number remaining are unused.
so number of invalid code sequences = 8192 - 512 = 7680.
| Bits | Quartenary Symbols |
| 00 | -3 |
| 01 | -1 |
| 10 | +3 |
| 11 | +1 |
![CALCULATIONS: 3. The input stream to a 2B/1Q encoder is 10 01 10 11, what is the output stream? [chapter 4] 4. How many invalid (unused) code sequences can we h CALCULATIONS: 3. The input stream to a 2B/1Q encoder is 10 01 10 11, what is the output stream? [chapter 4] 4. How many invalid (unused) code sequences can we h](/WebImages/23/calculations-3-the-input-stream-to-a-2b1q-encoder-is-10-01-1-1055590-1761550668-0.webp)