Suppose X is a random variable which follows Bin10p where 0
Suppose X is a random variable which follows Bin(10,p), where 0<p<1.
Find the value of p for which V(X) is as large as possible.
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Solution
As
V(x) = n p (1 - p)
Optimizing V(x) by setting V\'(x) = 0,
V\'(x) = n [(1-p) + (-p)] = 0
Cancelling n,
1 - 2p = 0
p = 1/2 [ANSWER]
