Just before noon your plasma glucose concentration was 100 m

Just before noon: your plasma glucose concentration was 100 mg dL^-1. This Plasma glucose is approximately evenly distributed among 3.5 L of plasma and 10.5 L of interstitial fluid that comprises your 14 L of ECF. Giocoso is readily distributed in both compartments. You drink a can of soda that contains 35 g of glucose. How much would you blood glucose rise if all the glucose in the soda was: absorbed and none of it was metabolized? Given that post-prandial (after eating) increases in blood glucose amount to maybe 40 mg dL^-1: depending on meal: over a period of an hour, give a crude estimate of the rate of glucose uptake by the peripheral tissues. Assume that the meal contains 100 g of carbohydrates and all of it is absorbed in one hour.

Solution

Plasma glucose concentration before noon (Fasting) = 100 mg dL^-1

This glucose is distributed in the plasma as well as interstitial fluid, that is the total ECF.

Concentration of glucose in ECF after consuming soda = (Total amount of glucose) / Total volume

= (35)gm/14 L

= 2.5 gm/L

= 250 mg/ dL

The percentage increase in glucose amount = 250 mg %

If within one hour, the glucose absorbtion process is complete, the amount of glucose unabsorbed in ECF =

Concentration of glucose (unabsorbed) x volume of ECF

= 40 mg/dL x 10dL/ L x 14 L

= 5600 mg = 5.6 g

Therefore, the amount of glucose taken up by the peripheral tissue, if the total was 100 grams of carbohydrate and 5.6 grams remained unabsorbed = 100 - 5.6 = 94.4 g/ hour