Simplify Leave your answers without negative exponents and i
Simplify. Leave your answers without negative exponents and in radical form or rational exponent form.
Solution
a) 64^2/3 = (8^2)^2/3 = 8^4/3
b) (3^-1/4)^-1 = 3^(-1*-1)/4^-1 = 3^1/4^-1
Now 3/4^-1 = 3*4^1 = 12
c) (sqrt8)^-2 = (8^1/2)^-2
= 8^(1/2*-2) = 8^-1 = 1/8
d) e^x*e^x = e^(x+x) = e^2x
e) (5x^0)/sqrt(5)
now x^0 =1
So, 5/sqrt5 ; rationalise denominator:
5sqrt5/sqrt5*sqrt5 = 5sqrt5/5 = sqrt5
f) sqrtx* (27x)^1/3
now 27= 3^3
So, sqrtx* (3^3)^1/3*(x^1/3) = x^(1/2+1/3)*3
= 3x^5/6
