A survey of 1692 randomly selected adults showed that 503 of

A survey of 1,692 randomly selected adults showed that 503 of them have heard of a new electronic reader. The accompanying technology display results from a test of the claim that 33% of adults have heard of the new electronic reader. Use the normal distribution as an approximation to the binomial distribution, and assume a 0.05 significance level to complete parts (a) through (e).

Sample proportion:

0.297281

Test statistic,

z: 2.8622

Critical z:

±1.96001.9600

P-Value:

0.0042

a. Is the test two-tailed, left-tailed, or right-tailed?

b. What is the test statistic?

c. What is the P-value?

d. What is the null hypothesis and what do you conclude about it? Identify the null hypothesis.

    A. : H0: p0.33

    B. H0: p=0.33

    C. H0: p<0.33

    D. H0: p>0.33

Choose the correct answer below.

    A. Reject the null hypothesis because the P-value is less than or equal to the significance level,.

    B. Fail to reject the null hypothesis because the P-value is less than or equal to the significance level, .

    C. Reject the null hypothesis because the P-value is greater than the significance level, .

    D. Fail to reject the null hypothesis because the P-value is greater than the significance level, .

e. What is the final conclusion?

    A.There is sufficient evidence to warrant rejection of the claim that 33% of adults have heard of the new electronic reader.

    B. There is not sufficient evidence to warrant rejection of the claim that 33% of adults have heard of the new electronic reader.

   C. There is sufficient evidence to support the claim that 33% of adults have heard of the new electronic reader.

   D.There is not sufficient evidence to support the claim that 33% of adults have heard of the new electronic reader.

Sample proportion:

0.297281

Test statistic,

z: 2.8622

Critical z:

±1.96001.9600

P-Value:

0.0042

a. Is the test two-tailed, left-tailed, or right-tailed?

b. What is the test statistic?

c. What is the P-value?

d. What is the null hypothesis and what do you conclude about it? Identify the null hypothesis.

    A. : H0: p0.33

    B. H0: p=0.33

    C. H0: p<0.33

    D. H0: p>0.33

Choose the correct answer below.

    A. Reject the null hypothesis because the P-value is less than or equal to the significance level,.

    B. Fail to reject the null hypothesis because the P-value is less than or equal to the significance level, .

    C. Reject the null hypothesis because the P-value is greater than the significance level, .

    D. Fail to reject the null hypothesis because the P-value is greater than the significance level, .

e. What is the final conclusion?

    A.There is sufficient evidence to warrant rejection of the claim that 33% of adults have heard of the new electronic reader.

    B. There is not sufficient evidence to warrant rejection of the claim that 33% of adults have heard of the new electronic reader.

   C. There is sufficient evidence to support the claim that 33% of adults have heard of the new electronic reader.

   D.There is not sufficient evidence to support the claim that 33% of adults have heard of the new electronic reader.

Solution

a) the test is two tailed test

b) the test Statistic is 2.8622

c) The P-value is 0.0042

d) The null hypothesis is H0 : P = 0.33

Reject the null hypothesis because the P-value (0.0042) is less than the significance level, (0.05).

e) There is sufficient evidence to warrant rejection of the claim that 33% of adults have heard of the new electronic reader.

A survey of 1,692 randomly selected adults showed that 503 of them have heard of a new electronic reader. The accompanying technology display results from a tes
A survey of 1,692 randomly selected adults showed that 503 of them have heard of a new electronic reader. The accompanying technology display results from a tes

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