A football team consists of 10 each freshmen and sophomores
Solution
Total number= 10+10+19+15 =54
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(1) 15C4/54C4 = (15*14*13*12)/(54*53*52*51) =0.004316
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(2) 10*10*19*15/ 54C4
=28500/ ((54*53*52*51)/(1*2*3*4))
=0.090118
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(3)10C2*10C2/54C4
=(10*9/2) *(10*9/2)/ ((54*53*52*51)/(1*2*3*4))
=0.006403
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(4)P(at least 1 of the students is a senior)
=1-P(no of the students is a senior)
=1-39C4/54C4
=1- (39*38*37*36)/(54*53*52*51)
=0.739919

