Fluid mechanicsDynamics of fluids An iceberg of 912 kgfm3 fl
Fluid mechanics/Dynamics of fluids
An iceberg of =912 kgf/m3 floats in the ocean (D.R.= 1.025) emerges from the water with a volume 300m3
a) Total volume of the iceberg?
b) Weight of the iceberg out of the water?
c) Apparent weight of the iceberg in the water?
d) Volume exposed out of water represented in percentage %?
600 m -912 Kgf/m3Solution
(a) Solution:-
Total volume of iceberg = 600 + 300 = 900 m3 Answer
(b) Solution:-
Weight of iceberg out of water = total volume * density of iceberg
Weight of iceberg out of water = 900 * 912 = 820.8 * 103 kg Answer
(c) Solution:-
Apparent weight of iceberg = weight of water displaced due to iceberg
Apparent weight of iceberg = 300 * density of sea water
Apparent weight of iceberg = 300 * 1024
Apparent weight of iceberg = 307.2 *103 kg Answer
(d) Answer:-
% volume exposed out of water = (600/900) *100
% volume exposed out of water = 66.67 Answer
