For a students t distribution with df10 and t2930 a find an

For a students t distribution with d.f.=10 and t=2.930,

a) find an interval containing the corresponding P-value for a two-tailed test. (answer should be:0.010<P-value<0.020)

b) find an interval containing the corresponding P-value for a left-tailed test. (answer should be: 0.005<P-value<0.010)

Please show all work.

Solution

The P-value corresponding to degrees of freedom 10 is P(T>2.93)=1-P(T<=2.93)=1-0.9925=0.0075

(from t standard tables)

The P-value for a two tailed test is 2* P(T>2.93)=2*0.0075 = 0.015

The P-value for a left tailed test is P(T>2.93)=1-P(T<=2.93)=1-0.9925=0.0075