FIGURE 2628 5 3 12 V 18 V 10 12 I3 5 In Fig 262S what is the

FIGURE 26-28 5 3 12 V 18 V 10 12 I3 5) In Fig. 26-2S, what is the value of the current 1? B) 0.29 A C) 0.89 A D) 0.32 A E) 0.61 A A) 0.11 A

Solution

From Kirchoff\'s Juction rule

I₁ =I₂+I₃

I₁-I₂-I₃=0----------------------1

Applying Kirchoff\'s voltage rule in left loop

12-5I₁-6-10I₂=0

5I₁+10I₂=6-------------------2

Applying Kirchoff\'s voltage rule in right loop

6+10I₂-8-3I₃=0

10I₂-3I₃=2---------------------3

solving 1,2 and 3 we get

I₁=0.61 A

I₂=0.29 A

I₃=0.32 A

So answer is I₁=0.61 A