When a consulting firm conducted a survey of 1100 employee a
Solution
1.
Note that
p^ = point estimate of the population proportion = x / n = 0.43
Also, we get the standard error of p, sp:
sp = sqrt[p^ (1 - p^) / n] = 0.014927096
Now, for the critical z,
alpha/2 = 0.05
Thus, z(alpha/2) = 1.644853627
Thus,
Margin of error = z(alpha/2)*sp = 0.024552887
lower bound = p^ - z(alpha/2) * sp = 0.405447113
upper bound = p^ + z(alpha/2) * sp = 0.454552887
Thus, the confidence interval is
( 0.4054 , 0.4546 ) [ANSWER, C]
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