Homework Soursedifferentiate log base 2 13x step by step please Im not gett
differentiate log base 2 (1-3x)
step by step please, I\'m not getting how the book gets its answer...
step by step please, I\'m not getting how the book gets its answer...
Solution
y =log2 (1 - 3x)
= ln (1 - 3x)/ ln (2)
y\' =1/ln2 * [d(1-3x)/dx *1/(1-3x)]
=[ (-3)/(1-3x) ] /ln 2
= -3/[ (ln 2)*(1 - 3x) ]
= 3/[(ln 2)*(3x-1)]
