Polydactyly 6 fingers is a dominant trait but appear less th

Polydactyly (6 fingers) is a dominant trait, but appear less than 1% of the population. Let\'s assume that P = .01 and p = .99-set up a Punnett square and show all probabilities of genotypes and phenotypes.

Solution

the three genotypes that we could get from the polydactyly trait are :

PP, Pp and pp

if it is given that P= .01 and p = 0.99, then

PP = 0.01 x 0.01 = 0.0001 or 0.01%

Pp = 0.01 x 0.99 = 0.0099 or 0.99%

pp = 0.99 x 0.99 = 0.9801 or 98.01 %

since the phenotype of PP and Pp would be same, we can add their probabilities.

therefore probability of having polydactyly is 0.0099 + 0.0001 = 0.01 or 1%

and the probability of not having polydactyly is 98.01%