Solar radiation has density of 2400 Wm2 The system is a 10 m

Solar radiation has density of 2400 W/m2. The system is a 10 m^2 system which produces 3 kW DC. Is this information enough to calculate panel efficiency, capacity factor, or derating factor, and what is value of the relevant parameter? If it is, please calculate.

Solution

Solution:-

Given

Density = 2400 W/m²

A = 10 m²

Power output = 3 kW

Panel efficiency(?) = Power output/(Incident radiation dencity * Area)

Panel efficiency = 3 *10³/(2400 * 10)

Panel efficiency = 12.5 %   Answer