Of the different genes represented by your mutants you are p
Solution
He cross a Shaven female, which is recessive bristle character of Drosophila (s), with a ebony male which is also recessive body colour of Drosophila sp.
Now genotype of Shaven female may be either s/s, e/e or s/s, e+/e+. Here s/s represents recessive character of bristle means shaven and e/e represents recessive body colour means ebony. Besides this e+/e+ means dominant character of body colour that is yellow-brown. But the body colour in shaven female is not given that mean it should be dominant. So, genotype of shaven female is s/s, e+/e+.
Genotype of Ebony male may be either s/s, e/e or s+/s+, e/e. Here s+/s+ means dominant and normal bristle. As here body colour is ebony so genotype of ebony colour will be recessive (e/e). And as there is no particular information about bristle in male so genotype of bristle will be dominant (s+/s+). so, genotype of ebony male is s+/s+, e/e.
Now if there is a cross between shaven female and ebony male, F1 generation will be:
Shaven Female Ebony Male
s/s, e+/e+ X s+/s+, e/e..........................................P
s+/s, e+/e ............................................F1
Now, the genotype of F1 gamete s+/s, e+/e is normal bristle yellow-brown body colour. As s+ is dominant over s, so the bristle is normal. Also e+ is dominnt over e means ebony so the body colour is normal ( yellow -brown).
So, the ans is [C].
