Find the Pa PIa PIIa PI ASN AOQ and ATI for a double samplin

Find the Pa, PIa, PIIa, PI, ASN, AOQ, and ATI for a double sampling plan where c1 = 1, c2 = 4, n1 = 120, and n2 = 180 if the actual fraction defective p = .005 and the lot size N = 2500.

b. Do you think it’s reasonable for the RQL to be 0.005? Justify your answer.

Pa = total probablity of accepting a lot=PIa+PIIa

P1a =Probability of accepting lot on the first sample by using excel

= B(1, 120,0.005, TRUE)=0.8784

PIIa = Probability of accepting lot on second sample

=1-(0.8784+0.0000054)=0.1215

Pa=0.99999

ASN=Average sample number=120+180*0.1215=141.88

AOQ = Average outgoing quality=

$Find the Pa, PIa, PIIa, PI, ASN, AOQ, and ATI for a double sampling plan where c1 = 1, c2 = 4, n1 = 120, and n2 = 180 if the actual fraction defective p = .005$

Find the Pa PIa PIIa PI ASN AOQ and ATI for a double samplin

Solution

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