How would I find the max allowable force that a locker door

How would I find the max allowable force that a locker door hinge can take? I\'m not sure if this would be the max torsional shear stress or what. Any ideas?

Solution

Tensile strength is the stress at which a material fail (under tension).For a material subjected to pure axial tension, the breaking strength is equal to the force applied to cause the failure divided by the smallest cross sectional area of the material. The formula is given as

Breaking strength = F / A ..................1

In the given case there will be shear force acting upon the hinge from the hinge is pinned. Allowable shear stress is about half the allowable tensile strength.

So , allowable force would be found by using equation 1 by knowing the material breaking strength of the the certain material and detemining the area . In this case shear stress will be applied on the hinges.