Create the following program using java or anything to compa
Create the following program using java, or anything to compare what i have been doing. Thanks
Write a program that accepts 9 values from the user in the range of 1 to 9. Store these values in a two-dimensional array of size 3*3. The program should display if the two-dimensional array is a magic square or not. A square is considered to be a magic square if all of its row, column and diagonal sums are equal. Create a method called magicSquare () that accepts the two-dimensional array with integers as input and returns true or false. For example: [[2, 7, 6], [9, 5, 1], [4, 3, 8]] is a magic square because all eight of the sums are exactly 15.Solution
MagicSquareTest.jaav
  
    import java.util.Scanner;
   
    public class MagicSquareTest {
   
       
        public static void main(String[] args) {
        Scanner scan = new Scanner(System.in);
            int rows = 3, cols = 3;
            int a[][] = new int[rows][cols];
            System.out.println(\"Enter matrix elements;\");
            for(int i=0; i<rows; i++){
                for(int j=0; j<cols; j++){
                    a[i][j] = scan.nextInt();
                }
            }
            System.out.println(\"Entered Matrix is:\");
            for(int i=0; i<rows; i++){
                for(int j=0; j<cols; j++){
                    System.out.print(a[i][j] +\" \");
                }
                System.out.println();
            }
            boolean result = magicSquare(a);
            if(result){
                System.out.println(\"Given matrix is magic square\");
            }
            else{
                System.out.println(\"Given matrix is not magic square\");
            }
        }
        public static boolean magicSquare(int a[][]){
            int rowSum[] = new int[a.length];
            int colSum[] = new int[a.length];
            int diagonalSum1 = 0;
            int diagonalSum2 = 0;
                  
            for(int i=0; i<a.length; i++){
                for(int j=0; j<a[i].length; j++){
                    rowSum[i] = rowSum[i]+a[i][j];
                }
            }
            for(int i=0; i<rowSum.length; i++){
                System.out.println(\"Row \"+i+\" sum is \"+rowSum[i]);
            }
            for(int i=0; i<a.length; i++){
                for(int j=0; j<a[i].length; j++){
                    colSum[i] = colSum[i]+a[j][i];
                }
            }
            for(int i=0; i<colSum.length; i++){
                System.out.println(\"Column \"+i+\" sum is \"+colSum[i]);
            }
              
            for(int i=0; i<a.length; i++){
                diagonalSum1 = diagonalSum1+a[i][i];
            }
            for(int i=0; i<a.length; i++){
                diagonalSum2 = diagonalSum2+a[i][a.length-1-i];
            }
            System.out.println(\"Diagonal Sum1: \"+diagonalSum1);
            System.out.println(\"Diagonal Sum2: \"+diagonalSum2);
            for(int i=0; i<rowSum.length-1; i++){
                if(rowSum[i] != rowSum[i+1])
                    return false;
            }
            for(int i=0; i<colSum.length-1; i++){
                if(colSum[i] != colSum[i+1])
                    return false;
            }
            if(diagonalSum1 != diagonalSum2)
                return false;
              
            return true;
            }
   
    }
Output:
Enter matrix elements;
 2 7 6 9 5 1 4 3 8
 Entered Matrix is:
 2 7 6
 9 5 1
 4 3 8
 Row 0 sum is 15
 Row 1 sum is 15
 Row 2 sum is 15
 Column 0 sum is 15
 Column 1 sum is 15
 Column 2 sum is 15
 Diagonal Sum1: 15
 Diagonal Sum2: 15
 Given matrix is magic square


