A man runs at a speed of 40 ms to overtake a standing bus He

A man runs at a speed of 4.0 m/s to overtake a standing bus. He is 6.0 meters behind the door at t=0. THe bus moves forward and continues with a constant acceleration of 1.2 m/s². How long does it take for the man to catch the door. If he starts out actually 10.0 meters from the door, will e ebr catch up runin at the sae peed?

Solution

Srelative = Urelative + 1/2*arelative*t^2

=> 6 = 4*t + 1/2*1.2*t^2

=> t = 1.26 sec    ( time to catch bus)

at X = 10 , t = 1.937 sec ( time to catch bus) also as it take more time so he can\'t reach there with same speed