Find Io in the circuit below SolutionHere to find the curren

Solution

Here to find the current through 2j ohm impedance we use current division formula

Io current through R1 = I*(R2/(R1+R2))

By above logic current Io = 2(1-j)/(1-j+2j)

= 2(1-j)/(1+j)

= 2(1-j)(1-j)/(1+j)(1-j)

= (1-j)(1-j)

= -2j

Therefore current Io is -2j