What does the following Scheme function do define y s lis co

What does the following Scheme function do?

(define (y s lis)

(cond ((null? lis) \'() )

((equal? s (car lis)) lis)

(else (y s (cdr lis)))

))

Solution

Answer:

(define(y s lis) ---> y returns the list which is given and in this list the leading elements are removed up but not including the first occurence of the parameter.