answer in details please Thank you Suppose fx 025 for 0Solu

answer in details please. Thank you!

Suppose f(x) = 0.25 for 0

Solution

Q2.

PDF of Uniform Distribution f(x) = 1 / ( b - a ) for a < x < b
b = Maximum Value
a = Minimum Value
Mean = a + b / 2
Standard Deviation = Sqrt ( ( b - a ) ^ 2 / 12 )

f(x) = 1/(b-a) = 1 / (5--1) = 1 / 6 = 0.1667
1)
Mean = a + b / 2 = 2
Standard Deviation = Sqrt ( ( b - a ) ^ 2 / 12 ) = 1.732
2)
P(X < 3) = (3--1) * f(x)
= 4*0.1667
= 0.667

answer in details please. Thank you! Suppose f(x) = 0.25 for 0SolutionQ2. PDF of Uniform Distribution f(x) = 1 / ( b - a ) for a < x < b b = Maximum Value

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