Fortynine items are randomly selected from a population of 5
Forty-nine items are randomly selected from a population of 500 items. The sample mean is 40 and the sample standard deviation 9.
Develop a 99% confidence interval for the population mean. (Round your answers to 3 decimal places.)
| Forty-nine items are randomly selected from a population of 500 items. The sample mean is 40 and the sample standard deviation 9. |
Solution
Note that
Margin of Error E = z(alpha/2) * s / sqrt(n)
Lower Bound = X - z(alpha/2) * s / sqrt(n)
Upper Bound = X + z(alpha/2) * s / sqrt(n)
where
alpha/2 = (1 - confidence level)/2 = 0.005
X = sample mean = 40
z(alpha/2) = critical z for the confidence interval = 2.575829304
s = sample standard deviation = 9
n = sample size = 500
Thus,
Margin of Error E = 1.036751296
Lower bound = 38.9632487
Upper bound = 41.0367513
Thus, the confidence interval is
( 38.9632487 , 41.0367513 ) [ANSWER]
