In a baseball game baseball dimond is a square with sides 27
In a baseball game, baseball dimond is a square with sides 27m. how far does the first player have to throw the ball to get a runner out a third base.
Solution
The answer to this is that the first baseman must throw 38.18 meters, if he is on first base, to a person standing on the third base bag. This can be found by using the Pythagorean Theorem.
If you draw out a diagram of the baseball diamond, you will see that the baselines from home to third and home to first make a right angle at home plate. This means that a line from third to first is the hypotenuse of a right triangle.
The two legs of the triangle are each 27 meters. Therefore:
27^2 + 27^2 = c^2 (the distance from 1st to 3rd).
1458 = c^2
c = 38.18
