Let B and C be two events such that PE086 and PC010 a Determ
Solution
1) mutually exclusive
so P(B U C) = P(B) + P(C)
2)independant then
P(A ? B) Solution: P(A) + P(B) ? P(A)P(B)

1) mutually exclusive
so P(B U C) = P(B) + P(C)
2)independant then
P(A ? B) Solution: P(A) + P(B) ? P(A)P(B)
