Consider the system yn 025 y n2 y n2 delta n with initial
Solution
Y(n)= (n)+0.25y(n-2) where y(-1) = 0 and y(-2) =2;
For n=0;
Y(0) = (0)+0.25y(0-2)
Y(0)= 1 + 0.25*2;
Y(0)=1.5;
The present out put depents on present input,past output so the system is stable
