Some other capacitor problems A 50 mu F and a 150 mu F capac

Some other capacitor problems, A. 5.0 mu F and a 15.0 mu F capacitor are connected in series and then this series combo is connected in parallel to a 25.0 mu F capacitor. What is the equivalent capacitance? What would be the voltage needed on a 10.0 F capacitor for it to store as much energy as a 1000 kg car traveling at 30.0 m/s? Five capacitors are connected in parallel, and then charged by an ideal battery of some voltage V, until each has charge q. If one of these three capacitors is then removed from the circuit, what would be the resulting charge on each remaining capacitor in the circuit?

Solution

Answer:

(a) Equivalence resistance = (5 x 15)/20 + 25 = 28.75 micro farad

(b) Energy needed per second for car = 1000 x 30 = 30000 Joule

30000 = 1/2* C* V²

6 x 10^{3 =} V²

   V = 77.45 volt

(c) Total voltage when each has charge q and capacitance c

V = 25 qc

Let after removing three charges, total capacitance = 2c and total charge is Q

then 25 qc = 2Qc

so Q = 25/2

then effective chage on each capacitor = 25/ (2 x2) = 6.25 Coulomb