Hi I was wondering if you could please assist me with this p

Hi I was wondering if you could please assist me with this problem.

Which of the following are correct?

22 + 32 = 5

x2y2 = x y

x2 + y2 = x + y

(22)(32) = 6

52 + 22 = 29

Solution

a) (22 + 32) = 5

==> (4 + 9) = 5

==> 13 = 5 False

b) (x2 y2) = x y

==> (x2 y2)1/2 = xy

==> (x2)1/2 (y2)1/2 = xy          since (ab)m = am bm

==> xy = xy True             since (am)n = amn

c) (x2 + y2) = x + y   False

d) (22)(32) = 6

==> [(22)(32)]1/2 = 6

==> (22)1/2 (32)1/2 = 6

==> (2)(3) = 6

==> 6 = 6 True

e) (52 + 22) = 29

==> (25 + 4) = 29

==> 29 = 29     True

Hi I was wondering if you could please assist me with this problem. Which of the following are correct? 22 + 32 = 5 x2y2 = x y x2 + y2 = x + y (22)(32) = 6 52 +

Get Help Now

Submit a Take Down Notice

Tutor
Tutor: Dr Jack
Most rated tutor on our site