Complete the table below on the basis of the conservation of

Complete the table below on the basis of the conservation of energy principle for a closed system.

FOR THE FIRST ROW OF THE TABLE----

Qin = 350 kJ, E1 = 1021 kJ, E2 = 860 kJ (E = E2 - E1 = 860 - 1021 = -161 kJ)

Wout = ? AND e2 - e1 = ?

MASS OF SYSTEM m (kg) IS NOT GIVEN, HENCE WE ASSUME IT TO BE UNIT MASS - THAT IS m = 1 kg

NOW AS PER THE ENERGY EQUATION OF THE CLOSED SYSTEM, WE USE BELOW FORMULAE--

Qin - Wout = E and e2 - e1 = E / m

So substituting values, we get Wout = Qin - E = 350 - (-161) = 350 + 161 = 511 kJ

& e2 - e1 = E / m = -161 / 1 = -161 kJ/kg

Therefore Wout = 511 kJ (Answer) and e2 - e1 = -161 kJ/kg (Answer)

FOR THE SECOND ROW OF THE TABLE---

Qin = 350 kJ, E1 = 550 kJ, Wout = 130 kJ, m = 5 kg (E = E2 - E1)

E2 = ? AND e2 - e1 = ?

NOW AS PER THE ENERGY EQUATION OF THE CLOSED SYSTEM, WE USE BELOW FORMULAE--

Qin - Wout = E and e2 - e1 = E / m

Substituting values in the above formula, we get E = Qin - Wout = 350 - 130 = 220 kJ

and since E = E2 - E1, we arrive at the substitution 220 = E2 - 550 which gives E2 = 220 + 550 = 770 kJ

Now as stated in formulae e2 - e1 = E / m, we get e2 - e1 = 220 / 5 = 44 kJ/kg

Therefore E2 = 770 kJ (Answer) and e2 - e1 = 44 kJ/kg (Answer)