Compute both binompdf11 035 4 and binomcdf11 035 4 AND THEN

Compute both binompdf(11, 0.35, 4) and binomcdf(11, 0.35, 4) AND THEN explain what each of the calculations find AND how they are different.

Binompdf(11,0.35,4) = 0.24276

It gives the probability of exact 4 success in 11 trials with p= 0.35, p is probability of success.

Binomcdf(11,0.35,4)=0.66831

It gives the cumulative probability of 1,2,3 and 4 success in 11 trials with p=0.35, p is probability of success.

Here binomcdf is greater than binompdf as the cdf calculates the cumulative all the probability till 4 and pdf calculate probability of exactly 4.