Homework Sourseplease walk me through it Im looking to learn not cheatSolut
please walk me through it, I\'m looking to learn, not cheat.
Solution
arctan(xy)=(1/(u^2+1))(du/dx) when u is xy (1/((x^2y^2))+1)(y+xy\')=2xy+y\'x^2 y+xy\'=(2xy+y\'x^2)((x^2y^2)+1) y+xy\'=2x^3y^3+2xy+x^4y^2y\'+y\'x^2 xy\'-x^4y^2y\'-y\'x^2=2x^3y^3+2xy-y y\'(x-x^4y^2-x^2)=2x^3y^3+2xy-y y\'=(2x^3y^3+2xy-y)/(x-x^4y^2-x^2) y\'=y(2x^3y^2+2x-1)/x(1-x^3y^2-x)
