A tank contains 90 kg of salt and 1000 L of water Pure water

A tank contains 90 kg of salt and 1000 L of water. Pure water enters a tank at the rate 6 L/min. The solution is mixed and drains from the tank at the rate 3 L/min. What is the amount of salt in the tank initially? Amount = 90 (kg) Enter an expression for the total amount of brine (salt-water) in the tank at a time t minutes after this process starts? Total number of liters of brine at time t = Let A represent the number of kg of salt in the tank at time t. Enter an expression for the concentration of salt in the tank at a time t minutes after this process starts? Concentration: Enter a differential equation to represent the rate at which the amount of salt is changing in the tank at time t. dA/dt Solve this differential equation and use the initial conditions to enter the model that gives the amount of salt in the tank at time t. Find the amount of salt in the tank after 4 hours. Amount = 63.4 (kg) Find the concentration of salt in the solution in the tank as time ap

Solution

a) 90 kgs

b) let the amount of mixed water x be the amount of pure water and y. 6x+3y

c)concentration=90 kgs/ 1000 litres

d)dA/dt= 6 dx/dt +3 dy/dt