Tornado wind with a speed of 300 fts flows across a tower wh

Tornado wind with a speed of 300 ft/s flows across a tower which has a nearly uniform cylindrical cross section. The tower has approximately a diameter of 3 ft and a hight 100 ft. Estimate the total force acting on the tower as a result of the tornado wind.

Solution

CALICULATION OF WIND FORCE ON CYLINDRICAL TOWER

THE TOWER IS MOSTLY AFFECTED BY HORIZONTAL FORCES OF TORNADO

THE FORCES CAN BE CALICULATED BY THE FOLLOWING EQUATION

F = 0.63 *C_d * A * V²

^WHERE C_D=THE DRAG COEFFICIENT FOR CYLINDER=0.8

A= CROSSECTIONAL AREA OF CYLINDER WHICH IS EFFECTED BY TORNADO WIND=H*D

H=HEIGHT OF CYLINDER=100FEET=30Meter

D=DIAMETER OF CYLINDER=3 FEET=0.9Meter

V=TORNADO WIND SPEED=300FEET/SECOND=90m/s

F=FORCE GENERATED BY THE WIND IN NEWTONS

THEREFORE

F= 0.63 *C_d * A * V^{2 =} 0.63*0.8*30*0.9*90 ²

=110224.8 NEWTON=110.224KN