For the circuit shown in the figure below in which RA 23 an

For the circuit shown in the figure below, in which R_A = 23 and R_B = 3 , find the current through and the potential difference across each resistor. Place your result in the table for east of reading.

Solution

R_B=3 ohms and 24 ohms are in parallel

1/R₁ =1/3 +1/24

R₁ = 2.67 ohms

6 and 2.67 ohms are in series

R₂=6+2.67 =8.67 ohms

R_A=23 ohms and 8.67 ohms are in parallel

1/R₃ =1/23 + 1/8.67

R₃=6.3 ohms

4 and 6.3 ohms are in series ,so equivalent resistance

R_eq = 4+6.3 =10.3 ohms

Total Current flowing in the circuit

I=V/R_eq=24/10.3 =2.33 A

So Current flowing through each resistor is

I₄=I=2.33 A

I₆=2.33*(23/23+8.67) =1.69 A

I_RA =2.33-1.69=0.64 A

I_RB=1.69*(24/3+24) =1.5 A

I₂₄=1.69-1.5 =0.19 A

Voltage across each resistor

V₄ = 2.33*4=9.32 Volts

V₆=1.69*6=10.14 Volts

V_RA=0.64*23=14.72 Volts

V_RB=1.5*3=4.5 V

V₂₄=0.19*24=4.56 Volts