4 PT 234526 Find L LC De T MO E PI and PC Stations and draw

4) P.T. 23+45.26 Find: L. LC, De, T. M.O., E, PI, and PC Stations and draw a sketch and label components of the curve gcometry.(20 points)

Solution

Simple curve
Given data
Intersection angle, = 34° 45\' 22\" = 34.757°
Radius of curve R, =435.2 ft
Station of PT =23+45.46
Calculations
Degree of curve D= 5729. 578 /R
5729.58 /435.2 =13.16ft
Length of curve L, =100 (/D )
= 264.11 ft
Chord length LC= 2R Sin( /2)
= 260.00 ft
Tangent length R tan ( /2)
= 136.22 ft
Exterior distance E = R [1/cos(/2)
= 20.82 ft
Middle distance M, = R [1 - cos( /2)
=19.87 ft
Station of PC, PI
Station of PI = PT - T
=( 23 +45.6) -(1+36.5)
22 + 9.04
Station of PC = PI - T
= (22 +9.04) - (1+36.5)
= 20 + 72.82