Compute an 82 C I for population mean when n 100 sample mea

Compute an 82% C. I. for population mean when n = 100. sample mean is 58.3 and standard deviation of the population is assumed to be known and is 3.0.

Solution

S.D = 3...STANDARD ERROR = 3 / SQRT(100) = 0.3....

Z-SCORE FOR 82% C.I = 1.340755...
lower limit = mean - ( z * Std. error ) = 57.89777....
upper limit = mean - ( z * Std. error ) = 58.70223.....
confidence interval = [ 57.89777 , 58.70223 ].........