Car a is traveling 60 mph and leaves 8 minutes before car b

Car a is traveling 60 mph and leaves 8 minutes before car b which is traveling 73 mph. How long before car b catches car a?

Solution

60*(t+8)=73t
t = 480/13
t=36.9231 minutes for car b to catch car a.
When car b started car a had already gone 8 miles.