dydx6y and find the particular solution satisfying the initi

Solution

dy/dx = 0.6y
Hence dy/y = 0.6dx
Hence if we integrate both sides we get
ln y = 0.6x + c
Hence y = Ke^0.6x

Now as per given condition y = 4 when x = 0;

This gives 4 = K*e⁰
Hence k = 4
^{We have y(x) = 4e0.6x}