Our class is to give a presentation on probability at an ope

Our class is to give a presentation on probability at an open house, for extra credit. Three students will be chosen, out of the 10 still enrolled. (show work)

A. If one person will be the speaker, one will create the power point presentation, and the third will answer questions afterwards, how many different selections from the class are there?

B. If none of the three students will have a specified role, how many selections will there be?

C. If you are to be one of the three students, with no specified roles, how many selections will there be?

D. If the students to participate are chosen randomly, what is the probability that you will be in the group (no specified roles)?

Solution

A.

As order matters here, we use permutations. Hence, we have

10P3 = 720 ways [ANSWER]

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B.

This time, as order does not matter, we use combinations. Hence,

10C3 = 120 [ANSWER]

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