Please help answer these for me only need your answers to do

Please help answer these for me. only need your answers to double-check mine.

Solution

(1-sin2x)/cos2x

(1- 2sinxcosx)/(cos^2x -sin^2x)

= ( sin^2x +cos^2x +2sinxcosx)/(cosx+sinx)(cosx -sinx)

= (sinx +cosx)^2/(cosx+sinx)(cosx -sinx)

= (sinx +cosx)/(cosx -sinx)

Option A

sin(22.5)

use dentity : cos2x = 1-2sin^2x

sinx = sqrt[(1-cos2x)/2]

sin22.5 = sqrt[(1 -cos45)/2]

= sqrt[1-1/sqrt2/2]

= sqrt[(sqrt2-1)/2sqrt2]

rationalise denominator by multiplying by num and den by sqrt2

= sqrt[ ( 2 - sqrt2)]/2

Option B

Option