It states Ill need to use the formula 49t2 vt s Approximat

It states I\'ll need to use the formula 4.9t^2 + vt = s.
Approximately how far will an object fall in 13 seconds(t) when thrown downward at an initial velocity of 10 meters per second(v) from a plane?

s(t) = 4.9t^2 + 10t
s(13) = 4.9*169 + 130
s(13) = 958.1 meters

$It states I\'ll need to use the formula 4.9t^2 + vt = s. Approximately how far will an object fall in 13 seconds(t) when thrown downward at an initial velocity$