Solve the triangle ABC if b 124 c 163 B 403 a 10978 Prev

Solve the triangle ABC if b = 124, c = 163, B = 403. a = 109.78 Preview ; A = 110.73 Preview Z6T = 29.27 Preview degrees; degrees;

Applying sine rule : b/sinB = c/sinC

124/sin40 = 163/sinC

sinC = 163*sin40/124 =0.845

C1 = 57.67 deg, C2 =180-57.67 = 122.33 deg

Angle A1 = 180 -B -C1 = 180 - 40 -57.67 = 82.3 deg

Angle A2 = 180 -B- C2 = 180 - 40 -122.33 = 17.67 deg

a1/sinA1 = c1/sinC1

a1 = sinA1*c1/sinC1 = 191.16

a2 = sinA2*c2/sinC2 = 58.53